Given the function f(X) = 5 sin (-2x + 540^o) - 4

Question

1. State the transformations
2. Show your transformation statement and table of values
3. State the domain and range of the function
4. Graph 2 cycles of the function

Answer 1

This is a negative sin graph so it starts at the midline goes down to minimum , back up to the midline then up to max and then back to midline to complete one full period

Amplitude is 5

vertical shift is down 4

so max is (-4+5)=1 and min is (-4-5) =-9

period = 2pi/b =pi (180degrees)

for phase shift set -2x+540=0 -2x =-540 x=270 degrees