J.R. S. answered 07/24/21
Ph.D. University Professor with 10+ years Tutoring Experience
HCl(g) + H2O ==> HCl(aq)
pH = 1.57
[H+] = 1x10-1.57 = 2.69x10-2 M
Since we have 250 ml, this is equal to 0.250 L, so the moles of HCl needed would be ....
2.69x10-2 mol/L x 0.250 L = 0.0067 moles HCl
Converting this to grams HCl using the molar mass of HCl, we have...
0.0067 moles HCl x 36.5 g / mol = 0.246 g HCl required (3 sig. figs.)