
William W. answered 07/24/21
Experienced Tutor and Retired Engineer
The standard sine function looks like this:
y = Asin[B(x - C)] + D where
A = amplitude
B = 2π/period
C = phase shift (or horizontal shift)
D = vertical shift (in other words y = D is the equation of the midline or principal axis)
So looking at the given equation:
y = 5sin(3x - 180°) - 2
we need to slightly modify it to fit our generic function above, Notice that I must factor out the "B" to get it correct.
so the slightly modified function is y = 5sin[3(x - 60°)] - 2
Now we can see that:
A = 5
B = 3 meaning that 3 = 2π/period or the period = 2π/3
C = 60° (to the right) or +60°
D = -2 so y = -2 is the equation of the principal axis (usually called the midline)
The min and max are calculated as D + A and D - A so that would be -2 + 5 (or 3) and -2 - 5 (or -7)
Divine M.
Can you please answer other questions i posted 1 day ago under trigonometry and trigonometric functions even though it is actuallysinusoidal07/25/21