Raymond B. answered 07/22/21
Math, microeconomics or criminal justice
x^2 + y^2 = r^2 = 1^2 = 1
x^2 + y^2 = 1
.6^2 + .8^2 = .36+.64 = 1
whatever the point (x,y), plug it into x^2 + y^2 and if it doesn't sum to 1, it's not a point on the circle.
.6^2 + .79^2 = about .99< 1 so it's not on the circle
x^2 + y^2 = 1
x=rcos(theta) y = rsin(theta)
cos^2(theta) + sin^2(theta) = 1
r^2cos^2(theta) + r^2sin^2(theta) = r^2