z = (0.32 - 0.3)/sqrt(0.3 * 0.7/95) = 0.4254
P(z > 0.4254) = 1 - P(z < 0.4254); determine probability from standard normal probability table or using statistical calculator
Jane .
asked 07/19/21Based on historical data, your manager believes that 30% of the company's orders come from first-time customers. A random sample of 95 orders will be used to estimate the proportion of first-time-customers. What is the probability that the sample proportion is greater than than 0.32?
Note: You should carefully round any z-values you calculate to 4 decimal places to match wamap's approach and calculations.
z = (0.32 - 0.3)/sqrt(0.3 * 0.7/95) = 0.4254
P(z > 0.4254) = 1 - P(z < 0.4254); determine probability from standard normal probability table or using statistical calculator
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.