Chemistry 122 j

Question

Consider aqueous solutions of the following substances: I. (4 pts)Write aqueous acid or base ionization reactions for each II. (2 pts) Identify the conjugate of the substance given

a) F-

b) HNO3

Answer 1

a) F- + H2O >>>>> HF + OH-

The F- ion is a weak base.

In this scenario the H2O acts as the acid donating a proton to the F- ion.

HF is the conjugate acid as it now has a proton H+) to donate and OH- is the conjugate base as it can can accept a proton (H+).

b) HNO3 + H2O >>>> H3O+ + NO3-

Here the HNO3 donates its proton to water forming the Hydronium ion and the polyatomic ion NO3-.

H3O+ is the conjugate acid as it can donate a proton (H+), and the NO3- is the conjugate base as it can accept a proton (H+).

Answer 2

a) HF + H₂0 → F^- + H₃O⁺

In this case, HF is the acid because it can donate a hydrogen, and F^- is the conjugate base because it can accept a hydrogen. H₂O is your base because it can accept a hydrogen, and H₃O⁺ is your conjugate acid because it can donate a hydrogen.

b) HNO₃ + H₂O → NO₃^- + H₃O⁺

HNO₃ is the acid because it can donate a hydrogen, and NO₃^- is the conjugate base because it can accept a hydrogen. H₂O is your base because it can accept a hydrogen, and H₃O⁺ is your conjugate acid because it can donate a hydrogen.

I hope this helps!