margin of error (ME) = z-critical * sqrt(phat * (1-phat)/n),
where z-critical = 1.96 for 95% confidence level
and phat = 0.83 as given.
plug in values and compute
Serena A.
asked 07/18/21If n=580 and p(p-hat) = 0.83, find the margin of error at a 95% confidence level.
margin of error (ME) = z-critical * sqrt(phat * (1-phat)/n),
where z-critical = 1.96 for 95% confidence level
and phat = 0.83 as given.
plug in values and compute
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