Calculate the molar concentration of the acid if 35.18mL of hydrochloric acid was required to neutralize 45.0 mL of 0.345 M lithium hydroxide

Answer 1

First, write the reaction taking place:

HCl + LiOH ==> H2O + LiCl ... balanced neutralization reaction

Next, find the moles of LiOH used:

45.0 ml x 1 L / 1000 ml x 0.345 mols/L = 0.0155 mols LiOH

Next, find moles HCl present:

0.0155 mols LiOH x 1 mol HCl / mol LiOH = 0.0155 mols HCl

Finally, calculate the molar concentration of HCl:

0.0155 mols HCl / 0.03518 L = 0.4417 M = 0.442 M (3 sig. figs.)