Tom K. answered 07/17/21
Knowledgeable and Friendly Math and Statistics Tutor
The tan 2a formula is tan 2x = 2 tan x/(1 - tan2 x)
We can then solve for the half-angle formula
2 x/(1 - x^2) = y
2x = y- x^2y
x^2y + 2x - y = 0
x = (-1 ± √(1 + y2))/y
tan x/2 = (-1 ± √(1 + tan2 x))/( tan x) = (-1 ± sec x))/( tan x)
Alternatively, we can use the sin and cos half-angle formulas, but then we must find sin and cos from tan.
Then, if we are in quadrant 3, tan of the half angle will be negative and tan x will be positive and sec x will be negative , so we use
(-1 + sec x))/( tan x)
As cot u = 1.878, tan u = 1/1.878 and sec u = -√(1 + (1/1.878)2)
tan x/2 = (-1 - √(1 + (1/1.878)2)/(1/1.878) =
1.878 (-1 - √(1 + (1/1.878)2) =
-1.878 - √(1 + 1.8782) =
-4.006