Solubility Products

Question

The molar solubility of PbCl₂ is 4.71⋅10^−5 M. Calculate the solubility of each ion in a saturated solution: 

___ M Pb^2+

___ M Cl^-

Answer 1

PbCl₂ ==> Pb²⁺(aq) + 2Cl^-(aq)

4.71x10^-5 M Pb²⁺

and since you have 2 moles Cl^- for each 1 mol Pb²⁺ ...

9.42x10^-5 M Cl^-