J.R. S. answered 07/15/21
Ph.D. University Professor with 10+ years Tutoring Experience
Chromium (Cr) has an atomic mass of 52 g/mol. Usually, hexavalent Cr is used in electroplating, i.e. Cr6+.
To get Cr(s) to be deposited, this means 6 mols of electrons per mol of Cr.
300 g Cr(s) x 1 mol Cr/52 g = 5.77 mols Cr(s)
5.77 mols Cr(s) x 6 mols e- / mol Cr = 34.6 mols of electrons needed
(Note: if for some reason your problem uses Cr2+ or Cr3+, the mols of electrons should be adjusted accordingly)
1 mol e- = 96,485 Coulombs
96,485 C/mol e- x 34.6 mols e- = 3,338,381 C required
1 amp = 1 coulomb/sec
1.50x103 A = 1.50x103 C/sec
3,338,381 C x 1 sec / 1500 C = 2226 seconds