Determine the identity of the daughter nuclide

Question

Determine the identity of the daughter nuclide from the beta decay of ²⁰⁹₈₂Pb?

Answer 1

A beta particle is essentially an electron (no mass and -1 charge)

We can write the general equation for beta decay as: ^A_ZX ==> ^A_Z+1Y + ⁰_-1ß

In the current problem, we have....

²⁰⁹₈₂Pb ==> ²⁰⁹₈₃ Y + ⁰_-1ß

So Y = Bi (bismuth) or ²⁰⁹₈₂Pb ==> ²⁰⁹₈₃ Bi + ⁰_-1ß