If the temperature of 9.2 L of a gas at 8.8 ºC falls by 6.2 Cº, what is the new volume of the gas if the pressure is constant?

Answer 1

Constant pressure = Charles Law:

V1/T1 = V2/T2

V1 = 9.2 L

T1 = 8.8ºC + 273 = 281.8K

V2 = ?

T1 = 8.8ºC - 6.2ºC = 2.6ºC + 273 = 275.6

Plug the above values into V1/T1 = V2/T2

and solve for V2 (answer will be in liters)