You know the standard deviation of the population and you are taking a sample greater than 30, so you can assume normal distribution of the sample --> z statistic.
You know that x avg = 91.8, you assume a mu of 90, you use a standard deviation for the sample of 10.26/10
You can look up in a table or use technology to find the probability of z > (xavg-μ)/σx . This will be the p value. If p < α, you reject the null hypothesis.