Raymond B. answered 07/14/21
Math, microeconomics or criminal justice
h=100t-5t^2
0 = 100t -5t^2
t(100-5t) =0
t=0 or 20 seconds to be at ground level
another way to work this is take the derivative and set =0, the double the time
h' = 100-10t = 0
t=10 seconds is when it's at maximum height. double that to get time when it hits the ground
2(10) = 20 seconds
If this problem involves meters, the usual acceleration due to gravity is -4.9t^2. You either rounded off to-5t^2 or you're not at sea level or you're not on earth but some similar planet.