Kevin L.

asked • 07/09/21

Geometry problem

Let ∆ABC be a triangle with AB = 65, BC = 70, and CA = 75. A semicircle Γ with diameter BC is constructed outside the triangle. Suppose there exists a circle ω tangent to AB and AC and furthermore internally tangent to Γ at a point X. The length AX can be written in the form m√n (m root n) where m and n are positive integers that are not divisible by the square of any prime. Find m + n.

Brenda D.

tutor
Is there a diagram or picture that goes with your question?
Report

07/09/21

Kevin L.

No there isn't. I'm sorry.
Report

07/09/21

Paul M.

tutor
Careful, Yohannes! The semicircle is constructed on BC, like a Norman window...so that is OK. The circle (labeled omega) is tangent to AC and AB AND internally to the semicircle. This still works OK. The center of circle omega must be on the bisector of angle A...and this still works OK. I have used DESMOS to construct the figure. Now I will see if I can solve the problem.
Report

07/10/21

Brenda D.

tutor
Agreed but I also assumed that constructing the diagram was part of the problem for the student that is why I asked the first question. Thanks Paul.
Report

07/10/21

Doug C.

I also constructed the diagram on Desmos and stumbled on the answer by trial and error. The fact that m and n must be integers seemingly has something to do with the solution. It will be interesting to see if one of us can figure it out! Here is what I have so far: desmos.com/calculator/y3fyebnzr8
Report

07/10/21

Brenda D.

tutor
Doug it looks like you have a perfect upside down right triangle formed between AB = 65 and the y-axis with a height of 56 and a base of 33 according to your coordinates, since point A is at (0,0). making the base of the right triangle II to the x-axis? The angle complementary to A has a sine(33/65) its 30.5, so A is 59.5.
Report

07/12/21

1 Expert Answer

By:

Doug C. answered • 07/12/21

Tutor
5.0 (1,555)

Math Tutor with Reputation to make difficult concepts understandable

Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.

OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.