J.R. S. answered 07/08/21
Ph.D. University Professor with 10+ years Tutoring Experience
There are several ways to find the limiting reactant. One of the easiest is to simply divide the moles of each reactant by the corresponding coefficient in the balanced equation, and whichever value is less, that is the limiting reactant. In this problem we have ...
N2 + 3H2 ==> 2NH3 ... balanced equation
For N2 we have 6.0 mols N2 ÷ 1 = 6.2
For H2 we have 6.0 mols H2 ÷ 3 = 2.0
Because 2.0 is less than 6.2 H2 IS THE LIMITING REACTANT
Another way is to calculate the moles of product produced from each reactant:
6.0 mols N2 x 2 mols NH3 / 1 mol N2 = 12 mols NH3
6.0 mols H2 x 2 mols NH3 / 3 mols H2 = 4 mols NH3
This shows that H2 is limiting