J.R. S. answered 07/07/21
Ph.D. University Professor with 10+ years Tutoring Experience
CH4(g) + H2O(g) → CO(g) + 3 H2(g)
This reaction is the only one that has ∆S > 0 because it shows 2 moles of gas on the reactant side going to 4 moles of gas on the product side. This represents an increase in entropy. All the other reactions shown have negative entropy.