tan a = 4/3, tan b =sqrt(3)/3...use Pythagorean theorem
and tan(a-b)=(tan-tan b)/(1+tan a tan b)
Kevin L.
asked 07/05/21Determine tan(a-b), given that cos a = 3/5, sin b = 1/2 and both a and b are in the first quadrant.
tan a = 4/3, tan b =sqrt(3)/3...use Pythagorean theorem
and tan(a-b)=(tan-tan b)/(1+tan a tan b)
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