given sec x=-4 and 90<x<180. find the value of each of the five trigonometric functions

Question

given sec x=-4 and 90<x<180. find the value of each of the five trigonometric functions

Answer 1

I chose to convert the sec to cos the reciprocal of sec (so reciprocal of -4 is -1/4);

then to solve for X = cos^-1(-1/4). Note, you will find this is 104.4775° which is in the second quadrant