Read the z-score from the standard normal probability table corresponding cumulative probability of 0.63 (0.33). That is your 63rd percentile.
Yasmine P.
asked 07/04/21Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C.
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P63, the 63-percentile. This is the temperature reading separating the bottom 63% from the top 37%.
P63 = °C
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