J.R. S. answered • 07/03/21
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∆Gº = -RT ln K
14.4 kJ = -(0.008314 kJ/mol-K)(309K) ln K
ln K = -5.605
K = 3.68x10-3
Justin G.
asked • 07/03/21Equilibrium Constant
Calculate the equilibrium constant at 36.0 °C for each of the following reactions from the value of ΔG° = 14.4 kJ.
I_2(s)+Cl_2(g)⟶2ICl(g)
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