J.R. S. answered 07/03/21
Ph.D. University Professor with 10+ years Tutoring Experience
∆Gº = -nFEºcell
n = mols electrons = 2 (see below)
F = Faraday constant = 96,485 C/mol e-
Eº = standard potential of the galvanic cell (see below)
Sn2+ + 2e- ==Sn(s) Eº = -0.14 V
Mn2+ + 2e- ==> Mn(s) Eº = -1.18 V
Eº = -0.14 - (-1.18) = 1.04 V
∆Gº = - (2 mol e-)(96,485 C/ mol e-)(1.04 V) = -200,689 C-V = -200,689 Joules
∆Gº = -201 kJ