Find the values of the trigonometric functions of 𝜃 from the information given. cos(𝜃) = 3/16 , sin(𝜃) < 0

Question

sin(𝜃) = 

 

 tan(𝜃) = 

 

 csc(𝜃) = 

 

 sec(𝜃) = 

 

 cot(𝜃) = 

 

 

Answer 1

opposite side = sqr(-a^2+ h^2) sqr(-3^2 +16^2) = sqr(256-9) = sqr247

sinx = o/h = -sqr247/16

cscx = h/o = -16/sqr247

secx = h/a = 16/3

tanx = o/a = -sqr247/3

cot x= a/o = -3/sqr247

angle x or theta is in quadrant IV where only cosines and secants are positive