Natalie G.
asked 07/01/21solving question
A spherical balloon is inflated with gas at a rate of 900 cubic centimeters per minute.
(a)
Find the rates of change of the radius when r = 70 centimeters and r = 85 centimeters.
| r = 70 | cm/min | ||
| r = 85 | cm/min |
2 Answers By Expert Tutors
Inactive Tutor answered 07/01/21
V = 4/3 πr3
dV/dt = 4/3 x 3 πr2 dr/dt = 4 πr2 dr/dt
dV/dt = 900 [ given] so you can find dr/dt for r = 70, 85 using the above equation
Inactive Tutor
Of course your use of implicit differentiation is maybe a little quicker than what I suggested. I like this approach.07/01/21
Inactive Tutor answered 07/03/21
V=(4/3)pi(r^3) take the derivative with respect to time
V'(t) =4pi(r^2)r'
r'(t) = V'/4pir^2
= 900/4pi(75)^2 = 225/pi(75)^2 = 225/pi(5625) = .04/pi = about .04/3.14 = .01327 cm/minute
when r=75
r'=900/4pi(85)^2 = 225/pi(7225) = about 0.03114/pi = .00991 cm per minute
when r=85
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Inactive Tutor
Please confirm that this is not for a graded assignment or test. It is unethical to provide or receive answers for such assignments. What I can give you is guidance. Your best first step is to write down all of the information that you know (in this case: the equation for the volume of a sphere and the constant rate of inflation). From this, you can create a differential equation representing the rate and then you can use the chain rule and some substitution to determine the rate of change of the radius with respect to time.07/01/21