J.R. S. answered 06/30/21
Ph.D. University Professor with 10+ years Tutoring Experience
Standard reduction potentials are as follows:
Li+ + e- ==> Li(s) Eº = -3.04 V
Mg2+ + 2e- ==> Mg(s) Eº = -2.38 V
Since the cell as written shows Mg2+ being reduced, it becomes the cathode and the Eºcell is...
-2.38 -(-3.04) = +0.66 V