electrochemistry

Question

Consider a galvanic cell consisting of:

Cu^2+ + 2e^-2 --> Cu 0.34

Zn^2+ + 2e^- --> Zn -0.76

Write the reaction occurring at the anode:

Write the reaction occurring at the cathode:

 Write the reaction for the galvanic cell: 

Calculate the E⁰_cell for the cell. 

Answer 1

Oxidation occurs at the anode

Reduction occurs at the cathode

Standard reductions potentials are as follows:

Cu²⁺ + 2e- ==> Cu(s) Eº = 0.34 V ... Cathode (reduction)

Zn²⁺ + 2e- ==> Zn(s) Eº = -0.76 V ... Anode (oxidation)

Reaction for galvanic cell:

Cu²⁺ + Zn(s) ==> Zn²⁺ + Cu(s)

Eº_cell = cathode - anode = 0.34 V - (-0.76 V) = 1.1 V