J.R. S. answered 06/30/21
Ph.D. University Professor with 10+ years Tutoring Experience
∆Gº = -nFEºcell
2Cr3+(aq) + 3Mg(s) ==> 2Cr(s) + 3Mg2+(aq) ... balanced equation
6 mols electrons are transferred = n
F = 96,500 C/mol e-
Eºcell = -0.74 + 2.38 = 1.64 V (calculated from standard reduction potentials for Mg2+ and Cr3+)
Solving for ∆Gº, we have...
∆Gº = -(6)(96,500)(1.64) = -949,560 coulomb-volts = -949,560 Joules = -950 kJ