J.R. S. answered 06/28/21
Ph.D. University Professor with 10+ years Tutoring Experience
∑products - ∑reactants
∑products = 2x9.64 + 10.21 = 29.49 kJ/mol
∑reactants = 2x-15.64 + -1.02 = -32.3 kJ/mol
∆Hreaction = 29.49 - (-32.3) = 61.8 kJ/mol
Secoya H.
asked 06/28/21Consider the following balanced reaction:
2 A2 + B → C + 2 D
What is the enthalpy of reaction if the enthalpy of formation of the compounds is given as
Compound | Enthalpy of Formation (kJ/mol) |
A2 | -15.64 |
B | -1.02 |
C | 10.21 |
D | 9.64 |
kJ/mol
J.R. S. answered 06/28/21
Ph.D. University Professor with 10+ years Tutoring Experience
∑products - ∑reactants
∑products = 2x9.64 + 10.21 = 29.49 kJ/mol
∑reactants = 2x-15.64 + -1.02 = -32.3 kJ/mol
∆Hreaction = 29.49 - (-32.3) = 61.8 kJ/mol
Tharindu M. answered 06/28/21
I am a professional tutor for chemistry and biology
H of reaction = H formation of products- H formation of reactants
= (9.64×2+ 10.21) - ( -1.02+ 2×-15.64)
= + 61.78kj mol^-
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