Calculus Homework Help

Question

where is f(x) = x-5 ÷ x²-3x-10 discountinous?

Answer 1

(x-5)/(x^2 -3x -10) = (x-5)/(x-5)(x+2)

f(x) is discontinuous at x =5 and x=-2

set the factors in the denominator = 0 and solve for x

any x value that makes the denominator =0 will be a discontinuity