What is an equation of the line that passes through the points (3, -3)(3,−3) and (6, -1)(6,−1)?

Answer 1

First find the slope m=(y_2-y_1)/(x_2-x_1)=(-1-(-3))/(6-3)=2/3

Use slope point form you have: y-(-3)=(2/3)(x-3) or

y+3=(2/3)x-2

y=(2/3)x-5

Answer 2

Use two-point form from Algebra 1

(y - (-3)) / (x - 3) = (-1 - (-3)) / (6 - 3)