What is the slope of a line perpendicular to the line whose equation is 3x+y=-53x+y=−5. Fully simplify your answer.

Answer 1

3x + y = -5

solve for y

y = -3x -5

slope of line of form y = mx + b, m is slope, so slope here is -3.

slope of perpendicular line is negative reciprocal or 1/3.