J.R. S. answered 06/18/21
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Cu2+(aq) + 2BTAS(aq) ==> [Cu(BTAS)2]2+(aq)
Keq = [Cu(BTAS)2]2+ / [Cu2+][BTAS]2
Mad B.
asked 06/17/21J.R. S. answered 06/18/21
Ph.D. University Professor with 10+ years Tutoring Experience
Cu2+(aq) + 2BTAS(aq) ==> [Cu(BTAS)2]2+(aq)
Keq = [Cu(BTAS)2]2+ / [Cu2+][BTAS]2
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