Ronny D.
asked 06/17/21Density Chemistry question (converting mol/L to %(m/m)
The density of the acetic acid (CH3COOH) solution is 1.05 g/mL. Calculate the %(m/m) of the acetic acid solution (convert mol/L to %(m/m)).
1 Expert Answer
J.R. S. answered 06/18/21
Ph.D. University Professor with 10+ years Tutoring Experience
Let us assume you have 1 L (1000 ml) of solution.
1.05 g / ml x 1000 ml = 1050 g of solution
Without knowing addition information, for example, the molarity, or the % w/v, etc. we cannot do any further calculations to determine % m/m or moles/L (M),
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Ronny D.
CH3COOH(aq) + NaOH(aq) = CH3COOHNa(aq) + H2O(L)06/17/21