Inactive Tutor answered 06/17/21
By cosine law cosA = 122 + 82 - 162)/(2·8·12) = - 0.25; so, A = cos-1(- 0.25) = 104.4775°;
sinA/16 = sinC/8; sinC = 8sin104.4775°/16; C = sin-1(sin104.4775°/2) = 28.9550°;
S = 180°- (A + C) = 46.5675°°
Ag S.
asked 06/16/21In ∆ACS, AC = 12, SA = 8 and SC = 16. Determine the measures of all the interior angles of the triangle.
Inactive Tutor answered 06/17/21
By cosine law cosA = 122 + 82 - 162)/(2·8·12) = - 0.25; so, A = cos-1(- 0.25) = 104.4775°;
sinA/16 = sinC/8; sinC = 8sin104.4775°/16; C = sin-1(sin104.4775°/2) = 28.9550°;
S = 180°- (A + C) = 46.5675°°
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