J.R. S. answered 06/17/21
Ph.D. University Professor with 10+ years Tutoring Experience
Cu(NO3)2(aq) + Na2S(aq) ==> CuS(s) + 2NaNO3(aq)
Whenever there is a precipitate (s) formed, the net ionic equation will contain the ions that make up that precipitate. In this case, that would be Cu and S making the solid CuS. So, the net ionic equation would be:
Cu2+(aq) + S2-(aq) ==> CuS(s)
Going through the entire process of writing the complete ionic and net ionic equations, it would be:
Cu2+(aq) + 2NO3-(aq) + 2Na+(aq) + S2-(aq) ==> CuS(s) + 2Na+(aq) + 2NO3-(aq) .. complete ionic
Cu2+(aq) + S2-(aq) ==> CuS(s) .. net ionic (after canceling spectator ions)