Model this situation with a linear system and solve: The perimeter of a rectangle is 234ft. When its length is doubled, the perimeter increases by 58 ft.

Answer 1

234= 2L + 2w = Perimeter, divide by 2 to get

117 = L + w

234 +58 = 4L +2w = new Perimeter when Length is doubled, divide by 2

117 +29 = 2L + w

subtract 1st equation from 2nd to eliminate one variable

29 = L. Length = 29 feet

w = 117-L = 117-29= 88 feet wide

check the solution

P = 2L +2w = 2(29)+2(88) = 58 +176 = 234

new P = 116 +176 = 292 =234+58 =58 more when L doubled,

Answer 2

234 = 2(L + W)

234 + 58 = 2(2L + W)

You do not specify for which variable to solve.