J.R. S. answered 06/16/21
Ph.D. University Professor with 10+ years Tutoring Experience
Look up the standard reduction potentials for Br and Mg. I find the following:
Mg2+ + 2e- ==> Mg(s) Eº = -2.38 V
Br2(l) + 2e- ==> 2Br-(aq) Eº = 1.07 V
Accordingly, Br2 will be reduced and Mg(s) will be oxidized in order to have a positive potential.
Br2 + 2e- ==> 2Br-
Mg ==> Mg2+ + 2e-
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Br2 + Mg ==> Mg2+ + 2Br- Eº = 1.07 + 2.38 = 3.45 V