Tom K. answered 06/15/21
Knowledgeable and Friendly Math and Statistics Tutor
There are 4! possible arrangements of each of the aces and kings, and 44!/(11!)^4 arrangements of the other cards.
We divide this by 52!/(13!)^4
This equals 24^2*44!/(11!)^4/(52!/(13!)^4) =
24^2 * (13*12)^4/P(52,8) =
2^14*3^6*13^4/(2^8*3^4*5^3*7^2*13*17*23*47) =
2^6*3^2*13^3/(5^3*7^2*17*23*47) =
1265472/112559125 =
0.0112