I need help with Stastics

Question

A jar contains 30 red marbles numbered 1 to 30 and 42 blue marbles numbered 1 to 42. A marble is drawn at random from the jar. Find the probability of the given event.

 The marble is red. P(red)=   

(b) The marble is odd-numbered. P(odd)=   

(c) The marble is red or odd-numbered. P(red or odd) =   

(d) The marble is blue or even-numbered. P(blue or even)

Answer 1

15 +21 odd = 36 odd out of 72 total

30/2 = 15 odd, 42/2 = 21 odd

30+42 72 total

odds of odd = 36/72 = 1/2 = 50% chance of picking an odd number

30 red but 15 are odd so that adds only 15 more positive outcomes

(36+15)/72 = 51/72 = Pr(R or Odd) = about 71% chance of Red or Odd

Pr(B or Even) = (42+15)/72 = 57/72 = about about 79% chance of blue or Even

Answer 2

15 +21 odd = 36 odd out of 72 total

30/2 = 15 odd, 42/2 = 21 odd

30+42 72 total

odds of odd = 36/72 = 1/2 = 50% chance of picking an odd number

30 red but 15 are odd so that adds only 15 more positive outcomes

(36+15)/72 = 51/72 = Pr(R or Odd) = about 71% chance of Red or Odd

Pr(B or Even) = (42+15)/72 = 57/72 = about about 79% chance of blue or Even