Yefim S. answered 06/11/21
Math Tutor with Experience
E(-4,8), F(8,4), G(5, -5) and H(-7,-1)
EG = √92 + 132 = 5√10, FH = √152 + 52 = 5√10. So diagonals EG and FH equel, EG = FH.
Then midpoint of EG is (1/2, 3/2) and midpoint of FH is (1/2, 3/2) or the same point. So diagonals bysect each other. From here we can conclude that EFGH is rectangle.