Stanton D. answered 06/12/21
Tutor to Pique Your Sciences Interest
Hi Justin G.,
There's some error in the terminology of your question. Half-lives refers to the inherent deterioration process of independent, randomly-decaying particles (usually radioactive nuclei). O.K., since the two given values are in 1:2 proportion, let's assume that there's an exponential decay of each item, and that "one half-life and two half-lives" is what is meant (not, "first half-life and second half-life"; do you see the issue?).
Then, you actually have excess data (the "rate constant") here; all you need is [A0] and the respective times (34.05 and 48.6) to calculate. I'm assuming you can set up and solve the exponential decay expression?
This incidentally forces both a and b to be 1, I think -- otherwise non-exponential behavior results ....
-- Cheers, --Mr. d.