Andre W. answered 06/09/21
Years of expertise!
Since tan(A) = 5/6
And equation of tangent = sine/cosine which we use to find the csc(A)
Set
tan(A)= (5)/(6)= (sin(A))/(cos(A))
we know tan (pi/4) = tan (45 degrees) = 1 (So the A should be around value 1 which is in radians)
given tan (A) = (sin(A))/(cos(A)) = (5)/(6) so sin(A) = 5
just plug in sin(A)=5 into cosecant equation : csc(angle in radians)=1/(sin(angle in radians)) :
1/(5)= 1/5 = csc(A)
is the answer!!
Adam B.
06/09/21
Andre W.
Well you ever thought that there can be a scalar in front of your trig values making it 5? Think outside the box06/09/21
Adam B.
06/09/21
Andre W.
it would be if there was a scalar (a number in front of sin(A) making it like 5sin(A) for example at ((pi)/2) radians = 90 degrees = 5(1) = 5 since sin(A) at 90 degrees is 1, but that is assuming the question is not written correctly06/09/21
Adam B.
06/09/21