Jsdfjs K.

asked • 06/09/21

Given tan A=5/6 and that angle A is in Quadrant I, find the exact value of csc A in simplest radical form using a rational denominator.

1 Expert Answer

By:

Andre W. answered • 06/09/21

Tutor
3.2 (13)

Years of expertise!

Adam B.

tutor
The sin(A) must be between -1 and +1 Sin(A)=5 is a grave and misleading mistake error call it whatever you want.
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06/09/21

Adam B.

tutor
( Sec A)^2= 1+ (tan A )^2 That is (sec A)^2= 61/36 Hence (cos A)^2 =36/61 and therefore (sin A)^2=25/61 That is sinA= 5/sqrt(61). Finally Csc(A)= (sqrt(61))/5.
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06/09/21

Andre W.

Well you ever thought that there can be a scalar in front of your trig values making it 5? Think outside the box
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06/09/21

Adam B.

tutor
Therefore is the statement : sin(A) = 5 , true ?
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06/09/21

Andre W.

it would be if there was a scalar (a number in front of sin(A) making it like 5sin(A) for example at ((pi)/2) radians = 90 degrees = 5(1) = 5 since sin(A) at 90 degrees is 1, but that is assuming the question is not written correctly
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06/09/21

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