What is the mass of a sample of neon gas that has a pressure of 0.77 atm, a volume of 18.95 L, and a temperature of 295 K?

Answer 1

To solve this problem, begin with the ideal gas law equation:

PV = nRT

(.77 atm)(18.95 L) = n(0.08206 L x atm/mol x K)(295 K)

Solving for n, the number of moles, we get 0.60 moles of neon.

To complete the problem, you then simply convert the moles of neon into grams of neon...

0.60 mol X 20.18 g/mol