What is the volume of 17.88 mol of argon gas at STP?

Answer 1

Good news...this problem can be solved in one quick and easy step.

At STP, 1.00 mole of an ideal gas occupies 22.42 liters.

Therefore, to solve this particular problem, one can simply multiply the given number of moles of gas by 22.42 L/mol:

17.88 mol X 22.42 L/mol