What volume does a 24.00 gram sample of helium gasoccupy at a pressure of 1.60 atm and at a temperatureof123°C?

Answer 1

Using grams you find moles of Helium.

24g/4gmol-1=6moles

To find the volume you use the gas equation: PV=nRT

n=6moles

R=0.08205L*atm/molK-1

P=1.6atm

T=396.15K

V=nRT/P

=6mole*0.08205L*atm/molK-1*396.15K/1.60atm=121.82L