The antiderivative is unique up to a constant.
If F(x)=∫f(x) dx and G(x)=∫f(x) dx, then F'(x)-G'(x)=0 which implies that F(x)=G(x)+C,
Eve K.
asked 06/08/21The question basically asks for a specific given interval, if the antiderivative of f exists, is it unique?
If yes, why?
If no, why not?
In stating the reasons you can use specific theorems that would help support your answer.
The antiderivative is unique up to a constant.
If F(x)=∫f(x) dx and G(x)=∫f(x) dx, then F'(x)-G'(x)=0 which implies that F(x)=G(x)+C,
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