Chemistry Unit 7 and 8

Question

1. Find the equilibrium constant, Kc, for the equation from the last problem: C12H26 (g) + O2 (g) ⇌ H2O (g) + CO2 (g)
2. [C12H26] = 1.8 x 103 M
3. [O2] = 8.6 x 103 M
4. [H2O] = 1.1 x 103 M

[CO2] = 1.1 x 103 M

Answer 1

In order to write the Kc expression, we first need to balance the equation. The balanced equation is:

2 C12H26 + 37 O2 <--> 26 H2O + 24 CO2

Therefore, the Kc expression is:

Kc = ([C12H26]^2 x [O2]^37) / ([H2O]^26 x [CO2]^24)

Assuming that these are the equilibrium concentrations, you can just plug in all the values and solve:

Kc = ([1.8 x 10^3]^2 x [8.6 x 10^3]^37) / ([1.1 x 10^3]^26 x [1.1 x 10^3]^24)

Kc = 1.04

I hope this helps!