sin^2(45+theta) + sin^2(45-theta) =2sintheta×costheta

Answer 1

1 - cos(2θ + 90°) + 1 - cos(90° - 2θ) = 2 + sin2θ - sin2θ = 2sin2θ; 2 = 2sin2θ; sin2θ = 1; 2θ = 90° + 360°·n;

θ = 45° + 180°·n, n = 0, ±1, ±2, ...

Answer 2

sin^2(45+theta) + sin^2(45-theta) =

the value 1 for any theta.

If the question was

sin^2(45+theta) - sin^2(45-theta) =

then there are steps to show it =2*sinθ*cosθ

let me know