An experimental study was conducted by a researcher to determine if a new time slot has an effect on the performance of pupils in mathematics.

Question

An experimental study was conducted by a researcher to determine if a new time slot has an effect on the performance of pupils in mathematics. Fifteen randomly selected learners participated in the study. Toward the end of the investigation, a standardized assessment was conducted. The sample mean was X = 85 and the standard deviation s = 3. In the standardization of the test, the mean was 75 and the standard deviation was 10. Based on the evidence at hand, is the new time slot effective?

Use a = 0.05.​

Answer 1

Ho: mean = 75

Ho: mean > 75

z = (sample mean - population mean)/(sample standard deviation/sqrt(sample size))

= (85 -75)/(3/sqrt(15) = 12.9

critical z for 0.05 is 1.96, so can reject null hypothesis and conclude new time slot effective.